Auto-Math
Si \(tg\,\theta=\dfrac{5}{12}\) alors \(cotg\, \theta=\)
\(\dfrac{12}{5} \)
\( \dfrac{5}{12} \)
\( \dfrac{7}{12} \)
n'existe pas
Résolvez l'équation \(tg\, 3x = \dfrac{\sqrt{3}}{3}\) .
\( S=\left\{\dfrac{\pi}{18}\right\} \)
\( S=\left\{\dfrac{\pi}{18}+k\dfrac{\pi}{3};\, k\in\mathbb{Z}\right\} \)
\( S=\left\{\dfrac{\pi}{18}+2k\dfrac{\pi}{3};\, k\in\mathbb{Z}\right\} \)
\( S=\left\{\dfrac{\pi}{18}+2k\pi;\, k\in\mathbb{Z}\right\} \)
Résolvez l'équation \(tg\, x =1\) .
\(S=\left\{\dfrac{\pi}{4}\right\} \)
\(S=\left\{\dfrac{\pi}{4}+k\pi;\, k\in\mathbb{Z}\right\} \)
\( S=\left\{\dfrac{\pi}{4},\, \dfrac{5\pi}{4}\right\} \)
\( S=\left\{\dfrac{\pi}{4}+2k\pi;\, k\in\mathbb{Z}\right\} \)
Si \(\sin\theta=\dfrac{3}{5} \) alors \(cotg\,\theta=\)
\( \dfrac{2}{5} \)
\( \dfrac{3}{4} \)
\( \dfrac{4}{3} \)
Résolvez l'équation \( \cos x = -{1\over 2} \).
\( S=\left\{\dfrac{2\pi}{3}\right\} \)
\( S=\left\{\dfrac{2\pi}{3},\, \dfrac{4\pi}{3}\right\} \)
\( S=\left\{\dfrac{2\pi}{3}+2k\pi,\, \dfrac{4\pi}{3}+2k\pi;\, k\in\mathbb{Z}\right\} \)
\( S=\left\{\dfrac{\pi}{3}+2k\pi,\, -\dfrac{\pi}{3}+2k\pi;\, k\in\mathbb{Z}\right\} \)
Convertissez en degrés l'angle\( \pi \over 12 \).
\(\dfrac{\pi}{15} \mbox{ degrés}\)
\(15 \mbox{ degrés}\)
\( 12 \mbox{ degrés}\)
\( 7,5 \mbox{ degrés}\)
Sans calculatrice, calculez \(\cos\theta\) si \(\theta=315^{\circ}\) .
\( \dfrac{\sqrt{2}}{2} \)
\( \dfrac{7\pi}{4} \)
\( \dfrac{1}{2} \)
\( -\dfrac{\sqrt{2}}{2} \)
Donnez la valeur de \(tg\,\left(\dfrac{2\pi}{3}\right) \).
\( 60 \)
\( \sqrt{3} \)
\( -\sqrt{3} \)
\( -\dfrac{\sqrt{3}}{3} \)
Si \(\alpha=53^{\circ}\) , alors le complémentaire de \(\alpha\) vaut
\( 37^{\circ}\)
\( 127^{\circ} \)
\( 143^{\circ} \)
\( 413^{\circ} \)
Résolvez l'équation \(\sin x = -1\) .
\(S=\left\{\dfrac{\pi}{2}\right\} \)
\( S=\left\{\dfrac{3\pi}{2}\right\} \)
\( S=\left\{\dfrac{3\pi}{2}+2k\pi;\, k\in\mathbb{Z}\right\} \)
\( S=\left\{\dfrac{\pi}{2}+2k\pi;\, k\in\mathbb{Z}\right\} \)
