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Factorisez \(ac+bc+ad+bd\)
\((a+d)(b+c)\)
\(a(b+c+d)\)
impossible
\((a+b)(c+d)\)
\((3a+2b)^2=\)
\(9a^2+12ab+4b^2\)
\(9a^2+4b^2\)
\(9a^2+4b^2+6ab\)
\(3a^2+2b^2+12ab\)
Factorisez \(ax^8-a\)
\(a(x^4-1)^2\)
\(a(x^2-1)^4\)
\(a(x-1)(x+1)(x^2+1)(x^4+1)\)
\(a(x-1)^8\)
Factorisez \(x^3+4x^2+5x+6\)
\((x+3)(x^2+x+2)\)
\((x-3)(x^2+x+2)\)
\((x^3+4x^2)(5x+6)\)
\(x(x^2+4x+5)+6\)
Factorisez \(a^3-b^3-a^2+b^2\)
\((a-b)(a^2+ab+b^2-a+b)\)
\((a-b)(a^2+ab+b^2-a-b)\)
\((a^2-b^2)(a-b-1)\)
\(a-b\)
Effectuez \((x+\frac{1}{x})^3\)
\(\dfrac{x^9+3x^4+3x^2+1}{x^3}\)
\(\dfrac{x^6+3x^4+3x^2+1}{x^3}\)
\(\dfrac{x^6+3x^5+3x+1}{x^3}\)
\(\dfrac{x^6+1}{x^3}\)
La division de \(x^5+x^4-3x^3-2+3x\) par \( x-x^3-1\) est-elle exacte ?
oui
non
je ne sais pas
Factorisez \(2x^3-x^2-18x+9=\)
\((2x-3)^3\)
\((2x-1)(x^2+9)\)
\((x-9)(x+9)(6x+1)\)
\((2x-1)(x-3)(x+3)\)
Effectuez \(3x-(2x^2+3)-[(2x+3x^2)-x+1]-(x-2)\)
\(-5x^2+x\)
\(-5x^2+x-2\)
\(x^2-x+2\)
\(-5x^2+x-5\)
Factorisez \(x^7-3x^5+3x^3-x\)
\(x(x-1)^3(x+1)^3\)
\(x(x^2-1)(x^4-3x^2-1)\)
\(x(x^2-1)(x^4-3x^3+x^2+1)\)
\(x^6-3x^4+3x^2-1\)
