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Le reste de la division de \( 3x^3-8x^2-5\) par \(x-4\) est
0
4
59
\(3x^2+4x+16\)
Le polynôme \(x^2-6x+5\) est divisible par
\(x+3\)
\(x-3\)
\(x+1\)
\(x-5\)
Déterminez \(a\), \(b\) et \(c\) pour que les deux polynômes soient égaux, \(P(x)=(a+1)x^2-bx+c\) et \(Q(x)=2ax^2+x+2b\).
\(a=1,b=1,c=2\)
\(a=1,b=-1,c=-2\)
\(a=\frac{1}{2},b=1,c=2\)
\(a=1,b=0,c=0\)
\((2x+1)^3=\)
\(4x^2+4x+1\)
\(8x^3+1\)
\(8x^3+12x^2+6x+1\)
\(8x^3+6x^2+6x+1\)
Effectuez \((-x+2)^3\)
\(8-x^3\)
\(8-6x+6x^2-x^3\)
\(8-12x+6x^2-x^3\)
\(x^3-6x^2+12x-8\)
\(x^3+8=\)
\((x+2)(x^2+2x+4)\)
\((x+2)^3\)
\((x-2)(x^2-2x+4)\)
\((x+2)(x^2-2x+4)\)
\((x^2-1)(x^2+1)=\)
\(x^4-2x^2+1\)
\(x^4+1\)
\(x^4-1\)
\(2x^2-1\)
Factorisez \( (x+y)(3a+2)-(x+y)\)
\((x+y)(3a+1)\)
\((x+y)^2(3a+2)\)
\(3a+2\)
\(3ax+x+3ay+y\)
\((\sqrt{2}-1)^3=\)
\(5\sqrt{2}-7\)
\(2\sqrt{2}-1\)
\(6\sqrt{2}-7\)
\(7-5\sqrt{2}\)
Effectuez \((x+3y)+(2x-5y)-(4x+2y)\)
\(-(x+4y)\)
\(-x\)
\(-5xy\)
\(-(x-4y)\)
