Auto-Math
Le reste de la division de \( x-x^3-1-2x^2\) par \(4+2x\) vaut
\(-\frac{1}{2}x^2+\frac{1}{2}\)
\(-2\)
\(0\)
\(-3\)
Factorisez \(x^7-3x^5+3x^3-x\)
\(x(x-1)^3(x+1)^3\)
\(x(x^2-1)(x^4-3x^2-1)\)
\(x(x^2-1)(x^4-3x^3+x^2+1)\)
\(x^6-3x^4+3x^2-1\)
Factorisez \(3(2-x)^2-3(x-2)^3\)
\(3(2-x)^2(7-3x)\)
\(3-x\)
\(3(2-x)^2(3-x)\)
\(-1-x\)
La division de \(x^5+x^4-3x^3-2+3x\) par \( x-x^3-1\) est-elle exacte ?
oui
non
je ne sais pas
Factorisez \(x^3+x^2+x+1\)
\(x^2(x+1)\)
\((x+1)(x^2+1)\)
\(x(x^2+x+1)+1\)
\((x+1)(x+1)(x-1)\)
Factorisez \(x^8+y^8+x^4y^4\)
\((x^4+y^4-x^2y^2)(x^4+y^4+x^2y^2)\)
\((x^2-y^2)^2(x^2+y^2)^2\)
\(x^4(x^4+y^4)+y^8\)
impossible
\((3a+2b)^2=\)
\(9a^2+12ab+4b^2\)
\(9a^2+4b^2\)
\(9a^2+4b^2+6ab\)
\(3a^2+2b^2+12ab\)
Factorisez \(2x^3-x^2-18x+9=\)
\((2x-3)^3\)
\((2x-1)(x^2+9)\)
\((x-9)(x+9)(6x+1)\)
\((2x-1)(x-3)(x+3)\)
Effectuez \((3a^2b^3c^2-4a^3c^4)^2\)
\(9a^4b^6c^4-16a^6c^8\)
\(9a^4b^9c^4+16a^9c^{16}-24a^5b^3c^6\)
\(9a^4b^6c^4+16a^6c^8-24a^5b^3c^6\)
\(9a^4b^6c^4+16a^6c^8-24a^6b^3c^8\)
Effectuez \(3x-(2x^2+3)-[(2x+3x^2)-x+1]-(x-2)\)
\(-5x^2+x\)
\(-5x^2+x-2\)
\(x^2-x+2\)
\(-5x^2+x-5\)
