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Si \(tg\, \theta=\dfrac{5}{12}\) alors la valeur absolue de \(\sin\theta=\)
\(\dfrac{5}{13} \)
\( \dfrac{7}{12} \)
\( \dfrac{12}{5} \)
\( -\dfrac{5}{12} \)
Convertissez en radians l'angle \(345^\circ \).
\(\dfrac{23\pi}{12} \mbox{ radians}\)
\( \dfrac{11\pi}{12} \mbox{ radians}\)
\( \dfrac{\pi}{345} \mbox{ radians}\)
\( 345 \mbox{ radians}\)
Si \(\sin\theta=\dfrac{3}{5} \) alors \(cotg\,\theta=\)
\( \dfrac{2}{5} \)
\( \dfrac{3}{4} \)
\( \dfrac{4}{3} \)
n'existe pas
\(\sin ({\pi \over 2}+a)= \)
\( \cos a \)
\(\sin a \)
\( 1+\sin a \)
\( -\cos a \)
Déterminez à l'aide du cercle trigonométrique la valeur de \( \cos\dfrac{3\pi}{4} \).
\( \dfrac{1}{2} \)
\( -\dfrac{1}{2} \)
\( \dfrac{\sqrt{2}}{2} \)
\( -\dfrac{\sqrt{2}}{2} \)
Convertissez en degrés l'angle \(2\pi \over 3\) .
\( \dfrac{1}{3} \mbox{ degrés}\)
\( \dfrac{2}{3}\mbox{ degrés}\)
\( 60\mbox{ degrés}\)
\( 120 \mbox{ degrés}\)
Convertissez en radians l'angle \(30^\circ \).
\(30\mbox{ radians}\)
\( \dfrac{\pi}{6} \mbox{ radians}\)
\( \dfrac{\pi}{3} \mbox{ radians}\)
\(\dfrac{\pi}{30}\mbox{ radians}\)
Convertissez en radians l'angle \(\normalsize 150^\circ\).
\(\dfrac{5\pi}{6}\mbox{ radians}\)
\(150\mbox{ radians}\)
\(\dfrac{5\pi}{3}\mbox{ radians}\)
\(\dfrac{\pi}{150}\mbox{ radians}\)
\(\sin (2\pi -a)= \)
\( \sin a \)
\( -\sin a \)
\(\cos a \)
\(2\pi-\sin a \)
Si \(\alpha=53^{\circ}\) , alors l'opposé de \(\alpha\) vaut
\( 35^{\circ} \)
\( 233^{\circ} \)
\( 413^{\circ} \)
\( -53^{\circ} \)
