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La division de \(x^5+x^4-3x^3-2+3x\) par \( x-x^3-1\) est-elle exacte ?
oui
non
je ne sais pas
Effectuez \((x+\frac{1}{x})^3\)
\(\dfrac{x^9+3x^4+3x^2+1}{x^3}\)
\(\dfrac{x^6+3x^4+3x^2+1}{x^3}\)
\(\dfrac{x^6+3x^5+3x+1}{x^3}\)
\(\dfrac{x^6+1}{x^3}\)
\(16a^4-8a^2+1=\)
\((4a^2-1)(4a^2+1)\)
\((4a^2-1)^2\)
\(8a^2(2a^2-1)\)
\((4a^4-1)^2\)
Effectuez \((x^4+\frac{a}{4})^2\)
\(x^8+\frac{a^2}{16}\)
\(x^8+\frac{a^2}{16}+\frac{1}{4}ax^4\)
\(x^{16}+\frac{a^2}{4}+\frac{1}{2}ax^4\)
\(x^8+\frac{a^2}{16}+\frac{1}{2}ax^4\)
Factorisez \(x^3-5x^2+5x-1=\)
\((x-1)^5\)
\((x-1)(x^2-6x+1)\)
\((x-1)(x^2-4x+1)\)
\((x-1)^3\)
Factorisez \(x^7-3x^5+3x^3-x\)
\(x(x-1)^3(x+1)^3\)
\(x(x^2-1)(x^4-3x^2-1)\)
\(x(x^2-1)(x^4-3x^3+x^2+1)\)
\(x^6-3x^4+3x^2-1\)
Factorisez \(6x-3x^2-3\)
\(3(x+1)^2\)
\(3(1-x)^2\)
\(x^2-2x+1\)
\(-3(x-1)^2\)
Factorisez \(2x^3-x^2-18x+9=\)
\((2x-3)^3\)
\((2x-1)(x^2+9)\)
\((x-9)(x+9)(6x+1)\)
\((2x-1)(x-3)(x+3)\)
\((3a+2b)^2=\)
\(9a^2+12ab+4b^2\)
\(9a^2+4b^2\)
\(9a^2+4b^2+6ab\)
\(3a^2+2b^2+12ab\)
Factorisez \(ax^8-a\)
\(a(x^4-1)^2\)
\(a(x^2-1)^4\)
\(a(x-1)(x+1)(x^2+1)(x^4+1)\)
\(a(x-1)^8\)
