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Déterminez \(a\), \(b\) et \(c\) pour que les deux polynômes soient égaux, \( P(x)=(a-2)x^3-3x^2-5(3-b)x+c\) et \(Q(x)=2x^3-3x^2+5x-12\).
\(a=4,b=4,c=-12\)
\(a=4, b=-4, c=-12\)
\(a=0,b=2,c=12\)
\(a=2,b=5,c=-12\)
\(8a^3-b^6=\)
\((2a-b^ 2)(4a^2+2ab^2+b^4)\)
\((2a-b^2)(4a^2+4ab^2+b^4)\)
\((2a-b^2)^3\)
\((2a-b^3)(4a^2+2ab^3+b^6)\)
\((\sqrt{3}-\sqrt{2})^2=\)
\(5-2\sqrt{5}\)
\(1\)
\(5-\sqrt{6}\)
\(5-2\sqrt{6}\)
Factorisez \( (x+y)(3a+2)-(x+y)\)
\((x+y)(3a+1)\)
\((x+y)^2(3a+2)\)
\(3a+2\)
\(3ax+x+3ay+y\)
Le quotient du polynôme \(x^3-x^2+x-6\) par \(x-2\) vaut
\(x^3-3x^2+x-20\)
\(x^2+x+3\)
\(x^3+x^2+3x\)
\(0\)
Factorisez \(x^4-y^6\)
\((x^2-y^3)^2\)
\((x^{\frac{4}{3}}-y^2)^3\)
\((x^2-y^3)(x^2+y^3)\)
\((x^2-1)(x^2+1)=\)
\(x^4-2x^2+1\)
\(x^4+1\)
\(x^4-1\)
\(2x^2-1\)
Factorisez \(x^8-x\).
\(x(x^7-1)\)
\(x^7-1\)
\(x(x-1)^7\)
\(x(x^3-1)(x^4-1)\)
\((a^3-b)(a^3+b)=\)
\(a^6+b^2-2a^3b\)
\(a^5-b^2\)
\(a^6+b^2\)
\(a^6-b^2\)
Le reste de la division de \(3x^2-5x+3\) par \(x+2\) vaut
\(-2\)
\(3x-11\)
\(5\)
\(25\)
