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Quel polynôme faut-il ajouter à \(x+5\) pour obtenir \(4x-1\) ?
\(3x+4\)
\(4x-6\)
\(3x-6\)
\(4-6\)
Effectuez \((x-1)(x^2+1)-x^3+(x^2-1)(x+x^2+1)-(x^3-1)x\)
\(x^3+x^2-x+2\)
\(x^3-x^2-x-2\)
\(0\)
\(x^3-x^2+x-2\)
L'évaluation du polynôme \(P(x)= -3x^2+x-4\) en \(x=\frac{1}{2}\) vaut
\(-5\)
\(-\frac{17}{4}\)
\(-\frac{5}{2}\)
\(-\frac{9}{2}\)
Effectuez \((3a^2b^3c^2-4a^3c^4)^2\)
\(9a^4b^6c^4-16a^6c^8\)
\(9a^4b^9c^4+16a^9c^{16}-24a^5b^3c^6\)
\(9a^4b^6c^4+16a^6c^8-24a^5b^3c^6\)
\(9a^4b^6c^4+16a^6c^8-24a^6b^3c^8\)
Factorisez \(x^7-3x^5+3x^3-x\)
\(x(x-1)^3(x+1)^3\)
\(x(x^2-1)(x^4-3x^2-1)\)
\(x(x^2-1)(x^4-3x^3+x^2+1)\)
\(x^6-3x^4+3x^2-1\)
Factorisez \(x^8+y^8+x^4y^4\)
\((x^4+y^4-x^2y^2)(x^4+y^4+x^2y^2)\)
\((x^2-y^2)^2(x^2+y^2)^2\)
\(x^4(x^4+y^4)+y^8\)
impossible
Effectuez \((4x^2-3x)+[2-(x+x^2)-3x^3]-[(2x-1)-x^3]\)
\(-4x^3+5x^2-6x+1\)
\(2x^3+3x^2-6x+3\)
\(-2x^3+3x^2-6x+3\)
Factorisez \((a+b)^3-(a+b)\)
\((a+b)(a^2+2ab+b^2)\)
\((a+b)^2\)
\((a+b)(a^2+2ab+b^2-1)\)
\(a^3+b^3-a-b\)
Factorisez \(6x-3x^2-3\)
\(3(x+1)^2\)
\(3(1-x)^2\)
\(x^2-2x+1\)
\(-3(x-1)^2\)
La division de \( x^4-3x+3x^3-1\) par \( x^2-1\) est-elle exacte ?
oui
non
je ne sais pas
