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Déterminez \(p\) pour que le reste de la division de \( x^3 +7x^2-px+4\) par \( x+2\) valle 2.
\(p=11\)
\(p=-11\)
\(p=19\)
\(p=-12\)
Factorisez \(x^4-y^6\)
\((x^2-y^3)^2\)
\((x^{\frac{4}{3}}-y^2)^3\)
\((x^2-y^3)(x^2+y^3)\)
\(0\)
Factorisez \(x^5-8x^3+16x\)
\(x(x^2+4)^2\)
\(x(x^4+16)^2\)
\(x(x+4)^2\)
\(x(x^2-4)^2\)
\((2x+1)^3=\)
\(4x^2+4x+1\)
\(8x^3+1\)
\(8x^3+12x^2+6x+1\)
\(8x^3+6x^2+6x+1\)
Le quotient du polynôme \(x^3-x^2+x-6\) par \(x-2\) vaut
\(x^3-3x^2+x-20\)
\(x^2+x+3\)
\(x^3+x^2+3x\)
Effectuez \((x^2+2x+9)-(x^2-4)+(x^2-x)\)
\(3x^2+x+13\)
\(x^2+x+13\)
\(x^2+x+5\)
\(x^2+x+12\)
\((\sqrt{2}+1)(\sqrt{2}-1)=\)
\(\sqrt{2}-1\)
\(2\sqrt{2}-1\)
\(1\)
\(2-2\sqrt{2}-1\)
Factorisez \(x^3+2x^2-1\)
\((x-1)(x^2+x-1)\)
\(x^2(x+2)-1\)
\((x+1)(x^2+x-1)\)
\((x+1)(x^4+1)\)
Déterminez \(a\), \(b\) et \(c\) pour que les deux polynômes soient égaux, \( P(x)=(a-2)x^3-3x^2-5(3-b)x+c\) et \(Q(x)=2x^3-3x^2+5x-12\).
\(a=4,b=4,c=-12\)
\(a=4, b=-4, c=-12\)
\(a=0,b=2,c=12\)
\(a=2,b=5,c=-12\)
Factorisez \((a+1)^2+2(a+1)\)
\(a+3\)
\((a+1)(a+3)\)
\(a^2+4a+3\)
\((a+1)(3a+3)\)
