Auto-Math
Déterminez à l'aide du cercle trigonométrique la valeur de \(\cos\dfrac{11\pi}{6} \).
\( \dfrac{1}{2} \)
\( -\dfrac{1}{2} \)
\( \dfrac{\sqrt{3}}{2} \)
\( -\dfrac{\sqrt{3}}{2} \)
Donnez la valeur de \(\cos {3\pi \over 4}\) .
\( -\dfrac{\sqrt{2}}{2} \)
\( \dfrac{\sqrt{2}}{2} \)
\( 135 \)
Si \(tg\,\theta=\dfrac{5}{12}\) alors \(cotg\, \theta=\)
\(\dfrac{12}{5} \)
\( \dfrac{5}{12} \)
\( \dfrac{7}{12} \)
n'existe pas
Si \(tg\, \theta=\dfrac{5}{12} \) alors \(\cos\theta=\)
\( \dfrac{13}{12} \)
\( \dfrac{12}{13} \)
Si \(\sin\theta=\dfrac{3}{5} \) alors \(cotg\,\theta=\)
\( \dfrac{2}{5} \)
\( \dfrac{3}{4} \)
\( \dfrac{4}{3} \)
Convertissez en degrés l'angle\( \pi \over 12 \).
\(\dfrac{\pi}{15} \mbox{ degrés}\)
\(15 \mbox{ degrés}\)
\( 12 \mbox{ degrés}\)
\( 7,5 \mbox{ degrés}\)
Si \(tg\, \theta=\dfrac{5}{12}\) alors la valeur absolue de \(\sin\theta=\)
\(\dfrac{5}{13} \)
\( \dfrac{12}{5} \)
\( -\dfrac{5}{12} \)
Résolvez l'équation \(\cos(3x+\pi) = \cos x \).
\( S=\left\{-\dfrac{\pi}{2}+k\pi,\, -\dfrac{\pi}{4}+k\dfrac{\pi}{2};\, k\in\mathbb{Z}\right\} \)
\( S=\left\{-\dfrac{\pi}{2},\, -\dfrac{\pi}{4};\, k\in\mathbb{Z}\right\} \)
\( S=\left\{-\dfrac{\pi}{2}+k\pi;\, k\in\mathbb{Z}\right\} \)
\( S=\left\{-\dfrac{\pi}{2}+2k\pi,\, -\dfrac{\pi}{4}+2k\dfrac{\pi}{2};\, k\in\mathbb{Z}\right\} \)
Convertissez en radians l'angle \(\normalsize 150^\circ\).
\(\dfrac{5\pi}{6}\mbox{ radians}\)
\(150\mbox{ radians}\)
\(\dfrac{5\pi}{3}\mbox{ radians}\)
\(\dfrac{\pi}{150}\mbox{ radians}\)
Donnez la valeur de \(tg\,\left(\dfrac{2\pi}{3}\right) \).
\( 60 \)
\( \sqrt{3} \)
\( -\sqrt{3} \)
\( -\dfrac{\sqrt{3}}{3} \)
