Auto-Math
L'évaluation du polynôme \(P(x)= -3x^2+x-4\) en \(x=\frac{1}{2}\) vaut
\(-5\)
\(-\frac{17}{4}\)
\(-\frac{5}{2}\)
\(-\frac{9}{2}\)
Factorisez \(x^8+y^8+x^4y^4\)
\((x^4+y^4-x^2y^2)(x^4+y^4+x^2y^2)\)
\((x^2-y^2)^2(x^2+y^2)^2\)
\(x^4(x^4+y^4)+y^8\)
impossible
Factorisez \(3(2-x)^2-3(x-2)^3\)
\(3(2-x)^2(7-3x)\)
\(3-x\)
\(3(2-x)^2(3-x)\)
\(-1-x\)
Effectuez \(3x-(2x^2+3)-[(2x+3x^2)-x+1]-(x-2)\)
\(-5x^2+x\)
\(-5x^2+x-2\)
\(x^2-x+2\)
\(-5x^2+x-5\)
Factorisez \(x^5+4-4x^3-x^2\)
\((x^3-1)(x^2+4)\)
\((x-1)(x^2+x+1)(x-2)(x+2)\)
Factorisez \(a-2b-ax+2bx\)
\((a-2b)(1-x)\)
\((a-2b)(-x)\)
\((a+2bx)(a-2bx)\)
\((a-2b)(1+x)\)
Effectuez \((-4x^2+2y^3)^2\)
\(16x^4+4y^5-16x^2y^3\)
\(16x^4+4y^6-16x^2y^3\)
\(4y^6-16x^4\)
\(4x^4+2y^6-8x^2y^3\)
Effectuez \((3a^2b^3c^2-4a^3c^4)^2\)
\(9a^4b^6c^4-16a^6c^8\)
\(9a^4b^9c^4+16a^9c^{16}-24a^5b^3c^6\)
\(9a^4b^6c^4+16a^6c^8-24a^5b^3c^6\)
\(9a^4b^6c^4+16a^6c^8-24a^6b^3c^8\)
Effectuez \((4x^2-3x)+[2-(x+x^2)-3x^3]-[(2x-1)-x^3]\)
\(-4x^3+5x^2-6x+1\)
\(2x^3+3x^2-6x+3\)
\(-2x^3+3x^2-6x+3\)
\(0\)
Quel polynôme faut-il ajouter à \(x+5\) pour obtenir \(42x^2\) ?
\(42x^2\)
\(37x\)
\(42x^2-x-5\)
