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Simplifiez l'expression \(\displaystyle{ \frac{(2a^2bx)(-3a^3b^2x^3)}{12a^5bx^2}}\).
\(-\dfrac{abx}{2}\)
\(-\dfrac{x^2}{3}\)
\(\dfrac{2-3abx^2}{12a^3x}\)
\(-\dfrac{b^2x^2}{2}\)
Si \(a=0,2\), \(b=-0,1\) et \(c=-0,5\), calculez \((\frac{a}{b}+\frac{b}{c})\cdot \frac{c}{a}\).
\(\dfrac{9}{2}\)
\(-\dfrac{4}{3}\)
\(0,03\)
\(-5\)
Calculez \(\displaystyle{\frac{\frac{6}{x}+3}{\frac{5}{x}-\frac{2}{x}}}\).
\(3\)
\(2+x\)
\(\dfrac{3x}{x+1}\)
\(0\)
L'opposé du carré du double de 0,4 est
\(0,64\)
\(-0,16\)
\(-0,64\)
\(-0,32\)
Calculez \(\left( \dfrac{1}{2}+\dfrac{6}{7}-\dfrac{1}{14}\right) \cdot \left( \dfrac{2}{3}-\dfrac{3}{4}\right)\).
\(-\dfrac{3}{28}\)
\(-\dfrac{6}{5}\)
\(-\dfrac{1}{28}\)
\(\dfrac{3}{28}\)
Calculez \(\dfrac{\sqrt{6}}{2\sqrt{3}-5\sqrt{2}}\).
\(2\sqrt{3}+\dfrac{15\sqrt{2}}{2}\)
\(-\dfrac{1}{19}(3\sqrt{2}+5\sqrt{3})\)
\(-\dfrac{3}{2}\)
\(\dfrac{3\sqrt{2}}{11}+\dfrac{5\sqrt{3}}{11}\)
Calculez \(\dfrac{\sqrt[4]{4a^4}}{\sqrt[3]{2a}}\).
\(\sqrt[5]{2}\sqrt[3]{a^2}\)
\(\sqrt[3]{\frac{a^2}{2}}\)
\(\sqrt[6]{2}\sqrt[3]{a^2}\)
\(\sqrt{2}a\)
Calculez \(\left(\dfrac{9}{-16}-\dfrac{-9}{16}\right)-\left(\dfrac{53}{24}-\dfrac{73}{36}\right)\).
\(-\dfrac{13}{72}\)
\(-\dfrac{5}{3}\)
\(\dfrac{5}{18}\)
Simplifiez l'expression \(\displaystyle{\sqrt[n]{\frac{a^{2n+1}}{b^{n+1}}}}\).
\(\displaystyle{\frac{b^{n^2+n}}{a^{2n^2+n}}}\)
\(\displaystyle{\frac{a^2\sqrt[n]{a}}{b\sqrt[n]{b}}}\)
\(\displaystyle{\frac{b^{2n+1}}{a^{3n+1}}}\)
\(\displaystyle{\frac{a^2+\sqrt[n]{a}}{b+\sqrt[n]{b}}}\)
Calculez \(\dfrac{3x+3y}{x^2-y^2}+\dfrac{7x-7y}{x^2-2xy+y^2}\).
\(\dfrac{10}{x-y}\)
\(\dfrac{10}{x+y}\)
\(\dfrac{10x-4y}{(x-y)^2}\)
\(\dfrac{10x-4y}{(x-y)^2(x+y)}\)